What is `DeltaU` when 2.0 mole of liquid water vaporise at `100^(@)C ` ? The heat of vaporistaion , `DeltaH` vap. of water at `100^(@)C` is `40.66 kJ mol^(-1)`.

What is `DeltaU` when 2.0 mole of liquid water vaporise at `100^(@)C `

1.	What is `DeltaU` when 2.0 mole of liquid water vaporise at `100^(@)C ` ? The heat of vaporistaion , `DeltaH` vap. of water at `100^(@)C` is `40.66 kJ mol^(-1)`.
Answer» Correct Answer - `DeltaE = 75.11 k J` `DeltaH= DeltaU + Deltan_(g)RT` `40.66 = DeltaU + 1 xx 8.314 xx 10^(-3) xx 373` `Deltan_(g)=1` `DeltaU = 37.555 xx 2 kJ` For two moles = 37.555 xx 2 = 75.11 kJ

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What is `DeltaU` when 2.0 mole of liquid water vaporise at `100^(@)C ` ? The heat of vaporistaion , `DeltaH` vap. of water at `100^(@)C` is `40.66 kJ mol^(-1)`.

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