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What is modified ampere's sircuital law ?

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Solution :It states that the line integral of the magnetic field `VECB` over a closed PATH is equal to `mu_0` TIMES the SUM of CONDUCTION current `I_C` and the displacement current `(I_D)` threading the closed path. `ointvecB.vecdl = mu_0 (I_C+I_D)


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