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What is ratio of Bohr magneton and nuclear magneton ? |
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Answer» `(m_(p))/(m_(e))` `mu_(B)=(EH)/(2m_(e))` `m_(e)`= electronic mass, e = electronic charge In nuclear physics magnetic moments associated with the spins of protons and neutrons are expressed in nuclear magnetons `(mu_(N))` `mu_(N)=(eh)/(2m_(p))` where `m_(p)` = mass of proton `rArr (mu_(B))/(mu_(N))=(m_(p))/(m_(e))` |
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