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What is ratio of Bohr magneton and nuclear magneton ?

Answer»

`(m_(p))/(m_(e))`
`(m_(p)^(2))/(m_(e)^(2))`
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`(m_(e))/(m_(p))`

Solution :MAGNETIC moment associated with electrons orbiting AROUND the NUCLEUS is given in terms of Bohr magneton `(mu_(B))`.
`mu_(B)=(EH)/(2m_(e))`
`m_(e)`= electronic mass, e = electronic charge In nuclear physics magnetic moments associated with the spins of protons and neutrons are expressed in nuclear magnetons `(mu_(N))`
`mu_(N)=(eh)/(2m_(p))` where `m_(p)` = mass of proton
`rArr (mu_(B))/(mu_(N))=(m_(p))/(m_(e))`


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