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What is the action of cone. HI on glucose? |
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Answer» Solution :When glucose reacts with concentrated hydroiodic acid in the presence of red · PHOSPHOROUS, complete reduction takes place and n-hexane is formed as a product. `underset("Glucose")(C_(6)H_(16)O_(6))overset(HI//P)underset("reduction")rarrCH_(3)-underset("n-hexane")(CH_(2))-CH_(2)-CH_(2)-CH_(3)` |
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