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What is the amount of charge possessed by `1 kg` of electronsA. `6.25xx10^(10)C`B. `1.76xx10^(11)C`C. `1.76xx10^(10)C`D. `1.25xx10^(10)C` |
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Answer» Correct Answer - b `n=(M)/(m_(e))= (1kg)/(9.1xx10^(-31))= 1.1xx10^(3)` Thereforre, charge on `1 kg` of electrons, `q= n e= 1.1xx10^(30)xx1.6xx10^(-19)= 1.76xx10^(11)C` |
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