What is the amount of heat to be supplied to prepare `128g` of `CaCO_(3)` by using `CaCO_(3)` and followed by reduction with carbon, Reactions are `CaCO_(3)(s)=CaO(s)+CO_(2)(g),DeltaH^(@)=42.8Kcal` `CaCO(s)=3C(s)=CaC_(2)+CO(g),DeltaH^(@)=111Kcal`A. `102.6Kcal`B. `221.78Kcal`C. `307.6Kcal`D. `453.46Kcal`

What is the amount of heat to be supplied to prepare `128g` of `CaCO_(

1.	What is the amount of heat to be supplied to prepare `128g` of `CaCO_(3)` by using `CaCO_(3)` and followed by reduction with carbon, Reactions are `CaCO_(3)(s)=CaO(s)+CO_(2)(g),DeltaH^(@)=42.8Kcal` `CaCO(s)=3C(s)=CaC_(2)+CO(g),DeltaH^(@)=111Kcal`A. `102.6Kcal`B. `221.78Kcal`C. `307.6Kcal`D. `453.46Kcal`
Answer» Correct Answer - A `CaCO_(3)(s)=CaO(s)+O_(2)(g)DeltaH^(@)=42.8Kcal` `(CaO(s)+3C(s)=CaC_(2)(s)+CO(g)DeltaH^(@)=111Kcal)/(CaCO_(3)(s)+3C(s)=CaC_(2)(s)+CO(g)+CO_(2)(g))` `DeltaH=153.8Kcal` Molecular weight of `CaC_(2)=40+24=64` `64g` of `CaC_(@)` requires `307.6Kcal` of heat `128g` of ` CaC_(2)` requires `307.6Kcal` of heat

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