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What is the angular momentum of an electron in the third orbit of an atom? |
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Answer» Solution :Here n = 3 , h = `6.6 xx 10^(-34)`JS ANGULAR momentum, `L = (NH)/(2pi) = (3 xx 6.6 xx 10^(-34))/(2 xx 3.14) = 3.15 xx 10^(-34)` Js |
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