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What is the area of the plates of a 2 F parallel plate capacitor given that the separation between the plates is 0.5 cm ? |
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Answer» Solution :Here C = 2F d = 0.5 cm = `5XX10^(-3)` m `in_(0)= 8.85 xx10^(-12) C^(2)N^(-1) m^(-2)` `C = (in_(0)A)/(d)` `:. A = (Cd)/(in_(0)) = (2xx5xx10^(-3))/(8.85xx10^(-12))= 1130xx10^(6) m^(2)` `:. A = 1130 (KM)^(2)` |
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