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What is the area of the plates of a 2 F parallel plate capacitor, given that the separation between the plates is 0.5 cm ? [You will realise from your answer why ordinary capacitors are in the range of uF or less. However, electrolytic capacitors do have a much larger capacitance (0.1 F) because of very minute seperation between the conductors.] |
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Answer» Solution :Here `C = 2 F, d = 0.5 cm = 5 XX 10^(-3) m` From the RELATION `C = (epsi_0A)/d`, we have AREA of each plate `A = (C.d)/(epsi_0) = (2 xx 5 xx 10^(-3))/(8.85 xx 10^(-12)) = 1.13 xx 10^9 m^2 or 1130 km^2`. |
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