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What is the area of the rhombus ABCD below if AC is equals to 6 cm and BC is equals to 4 cm |
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Answer» Answer: 15.9 cm² Step-by-step explanation: in ΔABC and ΔADC AB = AD (SIDES of a rhombus are EQUAL) AC = AC (common) BC = DC (sides of a rhombus are equal) ∴ ΔABC ≅ ΔADC (SSS congruency) AR(ΔABC) = 1/2(bh) = 1/2(6x√7) = 3√7 ∴ar(ΔADC) = 3√7 ∴ar(ABCD) = ar(ΔABC) + ar(ΔADC) = 3√7 + 3√7 = 6√7 = 6x2.65 = 15.9 cm² |
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