What is the area of the triangle if the vertices are (0,2), (0, 0), (3, 0)?(a) 1 sq.unit(b) 5 sq.units(c) 2 sq.units(d) 3 sq.unitsI have been asked this question in exam.I would like to ask this question from Area of a Triangle in section Determinants of Mathematics – Class 12

What is the area of the triangle if the vertices are (0,2), (0, 0), (3

1.	What is the area of the triangle if the vertices are (0,2), (0, 0), (3, 0)?(a) 1 sq.unit(b) 5 sq.units(c) 2 sq.units(d) 3 sq.unitsI have been asked this question in exam.I would like to ask this question from Area of a Triangle in section Determinants of Mathematics – Class 12
Answer» The correct ANSWER is (d) 3 sq.units The EXPLANATION is: The area of the triangle (0,2), (0, 0), (3, 0) with vertices is given by Δ=\(\frac{1}{2}\begin{Vmatrix}0&2&1\\0&0&1\\3&0&1\end{Vmatrix}\) Expanding ALONG R3, we get Δ=\(\frac{1}{2}\) {0-0+3(2-0)} Δ=3 sq.units.

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What is the area of the triangle if the vertices are (0,2), (0, 0), (3, 0)?(a) 1 sq.unit(b) 5 sq.units(c) 2 sq.units(d) 3 sq.unitsI have been asked this question in exam.I would like to ask this question from Area of a Triangle in section Determinants of Mathematics – Class 12

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