InterviewSolution
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InterviewSolution
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What is the average power of the discrete time periodic signal x(n) with period N?(a) \(\frac{1}{N} \sum_{n=0}^{N}|x(n)|\)(b) \(\frac{1}{N} \sum_{n=0}^{N-1}|x(n)|\)(c) \(\frac{1}{N} \sum_{n=0}^{N}|x(n)|^2\)(d) \(\frac{1}{N} \sum_{n=0}^{N-1}|x(n)|^2 \)This question was addressed to me during an internship interview.I need to ask this question from Frequency Analysis of Discrete Time Signal in section Frequency Analysis of Signals and Systems of Digital Signal Processing |
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Answer» The correct OPTION is (d) \(\FRAC{1}{N} \sum_{n=0}^{N-1}|x(n)|^2 \) |
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