What is the bond enthalpy of `Xe-F` bond ? `XeF_(4)(g)rarrXe^(+)(g)+F^(-)(g)+F_(2)(g)+F(g)," "Delta_(r)H=292"kcal/mol"` Given : Ionization energy of `Xe=279"kcal/mol"` `B.E.(F-F) = 30"kcal/mol"`, Electron affinity of F = 85 kcal/molA. 24 kcal/molB. 34 kcal/molC. `8.5` kcal/molD. None of these

What is the bond enthalpy of `Xe-F` bond ? `XeF_(4)(g)rarrXe^(+)(g)+F^

1.	What is the bond enthalpy of `Xe-F` bond ? `XeF_(4)(g)rarrXe^(+)(g)+F^(-)(g)+F_(2)(g)+F(g)," "Delta_(r)H=292"kcal/mol"` Given : Ionization energy of `Xe=279"kcal/mol"` `B.E.(F-F) = 30"kcal/mol"`, Electron affinity of F = 85 kcal/molA. 24 kcal/molB. 34 kcal/molC. `8.5` kcal/molD. None of these
Answer» Correct Answer - B `Delta_(r)H` = [Heat supplied] - [Heat evolved] `292=[4x + 279] - [38 + 85]` implies x = 34 kcal/mol

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What is the bond enthalpy of `Xe-F` bond ? `XeF_(4)(g)rarrXe^(+)(g)+F^(-)(g)+F_(2)(g)+F(g)," "Delta_(r)H=292"kcal/mol"` Given : Ionization energy of `Xe=279"kcal/mol"` `B.E.(F-F) = 30"kcal/mol"`, Electron affinity of F = 85 kcal/molA. 24 kcal/molB. 34 kcal/molC. `8.5` kcal/molD. None of these

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