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What is the Butterworth polynomial of order 1?(a) s-1(b) s+1(c) s(d) none of the mentionedThis question was addressed to me during an online exam.Query is from Butterworth Filters in section Digital Filters Design of Digital Signal Processing

Answer»

Right answer is (B) s+1

Explanation: Given that the order of the Butterworth low PASS filter is 1.

Therefore, for N=1 Butterworth POLYNOMIAL is given as B3(s)=(s-s0).

We know that, sk=\(e^{jπ(\frac{2k+1}{2N})} e^{jπ/2}\)

=> s0=-1

=> B1(s)=s-(-1)=s+1.



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