What is the change in Gibb’s free energy of a Cu-Zn system with a cell potential of 1.10V?(a) -11.13 KJ/mol(b) +21.23 KJ/mol(c) +11.13 KJ/mol(d) -21.23 KJ/molI got this question during an online interview.This intriguing question originated from Modern Theory Principles in division Modern Theory Principles of Corrosion Engineering

What is the change in Gibb’s free energy of a Cu-Zn system with a ce

1.	What is the change in Gibb’s free energy of a Cu-Zn system with a cell potential of 1.10V?(a) -11.13 KJ/mol(b) +21.23 KJ/mol(c) +11.13 KJ/mol(d) -21.23 KJ/molI got this question during an online interview.This intriguing question originated from Modern Theory Principles in division Modern Theory Principles of Corrosion Engineering
Answer» RIGHT ANSWER is (d) -21.23 KJ/mol The BEST I can explain: Given, Cell potential = 1.10V n=number of electrons INVOLVED in reaction = 2 F=96500 coulombs We know, ΔG=-nFEcell ΔG=-2965001.10 ΔG=-21.23 KJ/mol

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