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What is the formula to calculate rate of oxidation or rate of reduction during equilibrium?(a) r0=rR=i0nF(b) r0=rR=i0/nF(c) r0=rR=i0n/F(d) r0=rR=nF/i0This question was posed to me in a national level competition.Question is taken from Modern Theory Principles topic in chapter Modern Theory Principles of Corrosion Engineering

Answer»

Correct answer is (B) r0=rR=I0/nF

The best I can explain: Equilibrium is defined as the state at which rate of oxidation is equal to the rate of reduction. And the formula to calculate rate of oxidation or reduction is r0=rR=i0/nF where i0 is exchange current density, N is number of electrons INVOLVED and F is FARADAY’s constant.



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