1.

What is the current I in the circuit shown in adjoining Fig. ?

Answer»

2A
1.2A
1A
0.5A

Solution :Equivalent resistance R is given as
`1/R = 1/2 + (1)/((2 + 2 + 2)) = 1/2 + 1/6 rArr R = 1.5 Omega`
` THEREFORE I = (3V)/(1.5 Omega) = 2A`


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