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What is the current I in the circuit shown in adjoining Fig. ? |
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Answer» 2A `1/R = 1/2 + (1)/((2 + 2 + 2)) = 1/2 + 1/6 rArr R = 1.5 Omega` ` THEREFORE I = (3V)/(1.5 Omega) = 2A` |
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