1.

What is the current I shown in the given circuit?

Answer»

`(V )/(2R)`
`(V )/(R )`
`(V )/(16 R)`
`(V )/(8R)`

SOLUTION :Theequivalentcircuit diagramis asfollows

In loop4 weget ` R_1=(2 R xx2R )/(2R+ 2R) = R `
In loop3, weget` R_2= ((R+ R_1)xx 2 R)/(2 R+(R+R_1))=R `
In loop2 we get`R_3= ((R +R_2)xx 2 R)/( 2 R+(R + R_2))=R`
In loop1, weget ` R_4= R +R_3= R+ R =2R `
` thereforeI =(I_1)/( 8 )= (V //2 R) /(8 )= (V )/( 16 R )`


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