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What is the de-Broglie wavelength associated with an electron moving with an electron, accelerated through a potential difference of 100 volt? |
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Answer» Accelerating potential V = 100 V. The de Broglie wavelength `lambda` is `lambda=h//p=1.227/sqrtV nm` `lambda=1.227/sqrt100 nm =0.123 nm ` The de Broglie wavelength associated with an electron in this case is of N8the order of X-ray wavelengths. |
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