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What is the dead band of a single pole filter with a pole at 1/2 and represented by 4 bits?(a) (-1/2,1/2)(b) (-1/4,1/4)(c) (-1/8,1/8)(d) (-1/16,1/16)I have been asked this question during an online exam.My enquiry is from Round Off Effects in Digital Filters topic in division Digital Filters Design of Digital Signal Processing

Answer»

The correct choice is (d) (-1/16,1/16)

The explanation is: We KNOW that

|v(n-1)| ≤ \(\frac{(\frac{1}{2}).2^{-b}}{1-|a|}\)

Given |a|=1/2 and b=4 => |v(n-1)| ≤ 1/16=> The DEAD BAND is (-1/16,1/16).



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