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What is the derivative of sec^-1x w.r.t. x if x

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ANSWER:

\frac{dy}{dx}  { \sec }^{ - 1} x \\  \\  =   \frac{1}{x \sqrt{ {x}^{2}  + 1}  }  \\  \\  =  \frac{1}{ - x \sqrt{ {( - x)}^{2} + 1 }}   \:  \:  \: (cause \:  \: x <  - 1)\\  \\  = -   \frac{1}{x \sqrt{ {x}^{2} + 1 } }



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