1.

What is the diameter of sphere of 4V potential kept near the points situated at same distance from an electron ?

Answer»

`14.4 A^(@)`
`7.2 A^(@)`
`1.4 A^(@)`
`0.7 A^(@)`

Solution :`V= (KQ)/(R)`
`:. r=(ke)/(V)` ( Electric charge )
`:. 2r = (2ke)/(V) = (2xx9xx10^(9)xx1.6xx10^(-19))/(4)`
`:. "Radius " = 7.2 xx10^(10)m = 7.2 A^(@)`


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