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What is the difference between a=a+b and a+=b |
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Answer» The a=a+b statement has an assignment operator = and a arithmetic operator + while a+=b has a arithmetic assignment operator +=. Apart from this there is only a slight difference between the two. For similar integer or byte or float data TYPES both the expressions would compile. But if one value(a) is byte and the other(b) is int, a=a+b will not compile as byte+int is not byte On the other HAND, a+=b will compile as the arithmetic assignment operator will do an implicit type casting. Take for example, public class Example { public static void main(String []args) { byte a=2; int b=3; a=a+b; // generates an error as byte+int=int System.out.println(a); } }The above program generates an error $javac Example.java Example.java:7: error: INCOMPATIBLE types: possible LOSSY conversion from int to byte a=a+b; ^ 1 errorBut if we take a+=b public class Example { public static void main(String []args) { byte a=2; int b=3; a+=b; // compiles System.out.println(a); } }This code is error free and will generate the following output: $javac Example.java $java Example 5 |
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