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What is the directive gain when the magnitude of radiation intensity equals to average radiation intensity?(a) 4π(b) ∞(c) 1(d) 0I got this question in final exam.My doubt stems from Directive Gain topic in portion Antenna Parameters of Antennas

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Right option is (c) 1

Best explanation: Directive GAIN \(G_d = \FRAC{P_{d(\theta,\emptyset)}}{P_{AVG}} = \frac{P_{d(\theta,\emptyset)}}{P_r/4\pi r^2} = \frac{P_{d(\theta,\emptyset)^{r^2}}}{P_r/4\pi} = \frac{U_{d(\theta,\emptyset)}}{U_{avg}} \)

 ∴ \(G_d = \frac{U_{(\theta,\emptyset)}}{U_{avg}}\)=1.


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