1.

What is the directivity of half-wave dipole?(a) 1.64(b) 1.5(c) 1.43(d) 1.44The question was posed to me during an interview.This interesting question is from Directivity topic in chapter Antenna Parameters of Antennas

Answer»

Correct option is (a) 1.64

Easy explanation: DIRECTIVITY \(D=\FRAC{U_{max}}{U_{av}} = \frac{4\PI U_{max}}{P_{rad}} \)

Prad=36.54I0^2 Since the radiation resistance for Half-wave dipole is 36.54Ω.

Maximum radiation intensity is given by \(U_{max}=P_{max}.r^2=\frac{\mid E_\theta\mid_{max}^2}{2\eta}.r^2\)

Where \(E_\theta=\frac{j\eta I_0 e^{-jkr}cos⁡(\frac{\pi cos\theta}{2})}{2\pi rsin\theta}\)

⇨ \(D=\frac{4\pi}{1}\frac{\eta I_0^2}{8\pi^2} \frac{1}{36.54I_0^2}=1.64.\)


Discussion

No Comment Found

Related InterviewSolutions