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What is the electric field intensity at a distance of 20cm from a charge 2 X 10^-6 C in vacuum?(a) 250,000(b) 350,000(c) 450,000(d) 550,000The question was asked in an interview for internship.This intriguing question comes from Electric Field Intensity in section Electrostatic Fields of Electromagnetic Theory

Answer»

Correct option is (C) 450,000

Explanation: E = Q/ (4∏εor2)

= (2 X 10^-6)/(4∏ X εo X 0.2^2) = 450,000 V/m.



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