InterviewSolution
Saved Bookmarks
| 1. |
What is the electric flux linked with closed surface? A. `10^(11)N-m^(2)//C`B. `10^(12)N-m^(2)//C`C. `10^(10)N-m^(2)//C`D. `8.86xx10^(13)N-m^(2)//C` |
|
Answer» Correct Answer - b Electric flux, `phi= (q)/(epsilon_(0))` Where `q=` total charg e enclosed by closed surface `phi= (1.25+7+1-0.4)/(epsilon_(0))` `=(8.85C)/(8.85xx10^(-12)C^(2)N^(-1)m^(-2))` `10^(12)N-m^(2)//C` |
|