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What is the energy of a hydrogen atom in the first excited state if the potential energy is taken to be zero in the ground state?A. 10.2 eVB. 13.6 eVC. 23.8 eVD. 27.2 eV |
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Answer» Correct Answer - C Otherwise `U_1 =- 27.2 eV.` Therefore, we have increased it by 27.2 eV. It implies that we have increased it by 27.2 eV in all states. `U_2 = -6.8 eV` `:.U_2 = (-6.8+27.2) eV = +20.4 eV` `E_2 = U_2+K_2 =(20.4 +3.4) eV` = 23.8 ev. |
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