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A radioactive isotope is being produced at a constant rate `dN//dt=R` in an experiment. The isotope has a half-life `t_(1//2)`.Show that after a time `t gtgt t_(1//2)`,the number of active nuclei will become constant. Find the value of this constant.A. (a) ATB. (b) `A/T1n2`C. (c) AT 1n2D. (d) `(AT)/(1n2)` |
Answer» Correct Answer - D When the rate producion = rate of disintegration, number of nuclei or maximum. `:.` `lambdaN=A` or `(1n2)/TN=A` or `N=(AT)/(1n2)=`maximum |
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