1.

The energy released by the fission of a single uranium nucleus is 200 MeV. The number of fission of uranium nucleus per second required to produce 16 MW of power is (Assume efficiency of the reactor is 50%)A. (a) `2xx10^6`B. (b) `2.5xx10^6`C. (c) `5xx10^6`D. (d) None of these

Answer» Correct Answer - D
It means we are getting only 100 MeV of energy by the fission of one uranium nucleus.
Number of nuclei per second
=Energy required per second/Energy obtained by one fission
`=(16xx10^6)/(100xx1.6xx10^-13)=10^18`


Discussion

No Comment Found

Related InterviewSolutions