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What is the energy of a photon of wavelength λ?(a) hcλ(b) \(\frac {hc}{\lambda }\)(c) \(\frac {\lambda }{hc}\)(d) \(\frac {\lambda h}{c}\)The question was posed to me during a job interview.This interesting question is from Particle Nature of Light : The Photon topic in chapter Dual Nature of Radiation and Matter of Physics – Class 12

Answer»

Right choice is (b) \(\FRAC {HC}{\lambda }\)

Explanation: Energy of a photon, E = hv

V = \(\frac {c}{\lambda }\).

THEREFORE, E = \(\frac {hc}{\lambda }\)



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