1.

What is the energy of a photon whose wavelength is 6840 Å ?

Answer»

1.81 eV
3.6 eV
`-13.6 eV`
12.1 eV

SOLUTION :`E = h UPSILON = (HC)/(lambda) = (12400 eV Å)/(8840 Å) = 1.81 eV`


Discussion

No Comment Found

Related InterviewSolutions