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What is the energy of the electron revolving in third orbit expressed in eV? |
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Answer» 1.51 eV `E=(-2pi^(2) me^(4) Z^(2)K^(2))/(n^(2) h^(2))=-(13.6)/(n^(2)) eV` `E=-(13.6)/((3)^(2))=-(13.6)/(9)=1.51eV` (n=3 for 3RD Bohr.s orbit). |
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