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What is the Enthalpy change for a 20 Kg mole Nitrogen gas that is heated from 100 K to 200 K at constant pressure. (Cv = 2000 J/(Kg*mole)*(Degree Celsius))(a) 2*10^6(b) 4*10^6(c) 6*10^6(d) 8*10^6I had been asked this question in semester exam.Origin of the question is Enthalpy topic in division Energy Balances of Chemical Process Calculation

Answer»

The correct OPTION is (d) 8*10^6

To explain I would say: H2 – H1 = nCp(T2-T1).



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