1.

What is the equation for magnitude frequency response |H(jΩ)| of a low pass chebyshev-I filter?(a) \(\frac{1}{\sqrt{1-ϵ T_N^2 (\frac{Ω}{Ω_P})}}\)(b) \(\frac{1}{\sqrt{1+ϵ T_N^2 (\frac{Ω}{Ω_P})}}\)(c) \(\frac{1}{\sqrt{1-ϵ^2 T_N^2 (\frac{Ω}{Ω_P})}}\)(d) \(\frac{1}{\sqrt{1+ϵ^2 T_N^2 (\frac{Ω}{Ω_P})}}\)This question was posed to me in unit test.This interesting question is from Chebyshev Filters in chapter Digital Filters Design of Digital Signal Processing

Answer»

The correct option is (d) \(\FRAC{1}{\sqrt{1+ϵ^2 T_N^2 (\frac{Ω}{Ω_P})}}\)

The explanation is: The magnitude frequency response of a low pass CHEBYSHEV-I filter is GIVEN by

|H(jΩ)|=\(\frac{1}{\sqrt{1+ϵ^2 T_N^2(\frac{Ω}{Ω_P})}}\)

where ϵ is a parameter of the filter related to the ripple in the pass band and TN(x) is the N^th ORDER chebyshev polynomial.



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