What is the equation of the line that passes through the point (-3,0)

1.	What is the equation of the line that passes through the point (-3,0) and has a slope of 4/3 ?
Answer» ANSWER: Given, slope=−4/3 The LINE passes through the POINT (−3,4)=(x 1 ,y 1 ) Now, on substituting the values in y−y 1 =m(x−x 1 ), we have y−4=−4/3(x+3) 3y−12=−4x−12 4x+3y=0 Hence, the above is the REQUIRED line EQUATION.

What is the equation of the line that passes through the point (-3,0) and has a slope of 4/3 ?

Answer»

Given, slope=−4/3

The LINE passes through the POINT (−3,4)=(x

)

Now, on substituting the values in y−y

=m(x−x

), we have

y−4=−4/3(x+3)

3y−12=−4x−12

4x+3y=0

Hence, the above is the REQUIRED line EQUATION.