1.

What is the equation of the line which passes through (4, -5) and is perpendicular to `3x+4y+5=0` ?A. `4x-3y-31=0`B. `3x-4y-41=0`C. `4x+3y-1=0`D. `3x+4y+8=0`

Answer» Correct Answer - A
`3x+4y+5=0` or `y=(-3)/4 x+ (-5)/4`
Slope `=(-3)/4`
Slope of required line, `m=(-1)/(- 3/4)=4/3`
Also line passes through `(4, -5)`
Equation of line, `y+5=4/3 (x-4)`
`implies 3y+15=4x-16`
`implies 4x-3y-31=0`


Discussion

No Comment Found

Related InterviewSolutions