InterviewSolution
Saved Bookmarks
| 1. |
What is the equation of the line which passes through (4, -5) and is perpendicular to `3x+4y+5=0` ?A. `4x-3y-31=0`B. `3x-4y-41=0`C. `4x+3y-1=0`D. `3x+4y+8=0` |
|
Answer» Correct Answer - A `3x+4y+5=0` or `y=(-3)/4 x+ (-5)/4` Slope `=(-3)/4` Slope of required line, `m=(-1)/(- 3/4)=4/3` Also line passes through `(4, -5)` Equation of line, `y+5=4/3 (x-4)` `implies 3y+15=4x-16` `implies 4x-3y-31=0` |
|