InterviewSolution
Saved Bookmarks
| 1. |
What is the equation of the straight line parallel to `2x+3y+1=0` and passes through the point (-1, 2) ?A. `2x+3y-4=0`B. `2x+3y-5=0`C. `x+y-1=0`D. `3x-2y+7=0` |
|
Answer» Correct Answer - A The equation of line parallel to `2x+3y+1=0` is `2x+3y+K=0` It is passing through point (-1, 2) `:. 2(-1)+3(2)+K=0` `implies -2+6+K= 0 implies K=-4` `:.` Eqn. is `2x+3y-4=0` |
|