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What is the equation of the straight line parallel to `2x+3y+1=0` and passes through the point (-1, 2) ?A. `2x+3y-4=0`B. `2x+3y-5=0`C. `x+y-1=0`D. `3x-2y+7=0`

Answer» Correct Answer - A
The equation of line parallel to
`2x+3y+1=0` is `2x+3y+K=0`
It is passing through point (-1, 2)
`:. 2(-1)+3(2)+K=0`
`implies -2+6+K= 0 implies K=-4`
`:.` Eqn. is `2x+3y-4=0`


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