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    				| 1. | What is the equation of the straight line which passes through the point of intersection of the straight lines `x+2y=5` and `3x+7y=17` and is perpendicular to the straight line `3x+4y=10` ?A. `4x+3y+2=0`B. `4x-y+2=0`C. `4x-3y-2=0`D. `4x-3y+2=0` | 
| Answer» Correct Answer - D Intersecting lines are : `x+2y=5` & `3x+7y=17` On solving these we get : `x=1` & `y=2` Equation of perpendicular line is `3x+4y=10 or y=(-3)/4x+10` So, slope `=(-3)/4` `implies` Slope of required line `=4/3` `:.` Equation of given line is `(y-2)=4/3 (x-1) or 4x-3y+2 =0` | |