What is the equation of the tangent at a specific point of y^2 = 4ax at (0, 0)?(a) x = 0(b) x = 1(c) x = 2(d) x = 3I got this question during an interview for a job.Question is from Calculus Application in division Application of Calculus of Mathematics – Class 12

What is the equation of the tangent at a specific point of y^2 = 4ax a

1.	What is the equation of the tangent at a specific point of y^2 = 4ax at (0, 0)?(a) x = 0(b) x = 1(c) x = 2(d) x = 3I got this question during an interview for a job.Question is from Calculus Application in division Application of Calculus of Mathematics – Class 12
Answer» Correct ANSWER is (a) x = 0 Explanation: Equation of the given parabola is y^2 = 4ax ……….(1) DIFFERENTIATING both SIDE of (1) with respect to x we get, 2y(dy/dx) = 4a Or dy/dx = 2a/y Clearly dy/dx does not EXIST at (0, 0). Hence, the tangent to the parabola (1) at (0, 0) is parallel to y axis. Again, the tangent passes through (0, 0). Therefore, the REQUIRED tangent to the parabola (1) at (0, 0) is the y-axis and hence the required equation of the tangent is x = 0.

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