1.

What is the equation to the sphere whose centre is at (–2, 3, 4) and radius is 6 units? a. x2 + y2 + z2 + 4x –6y –8z = 7  b. x2 + y2 + z2 + 6x –4y –8z = 7  c. x2 + y2 + z2 + 4x –6y –8z = 4  d. x2 + y2 + z2 + 4x + 6y + 8z = 4 

Answer»

Correct option a. x2 + y2 + z2 + 4x –6y –8z = 7

Explanation:

(x + 2)2 + (y – 3)2 + (z – 4)2 = 62 

⇒ x2 + y2 + z2 + 4x – 6y – 8z = 62 – 22 – 32 – 4

⇒ x2 + y2 + z2 + 4x – 6y – 8z = 7



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