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What is the equation to the sphere whose centre is at (–2, 3, 4) and radius is 6 units? a. x2 + y2 + z2 + 4x –6y –8z = 7 b. x2 + y2 + z2 + 6x –4y –8z = 7 c. x2 + y2 + z2 + 4x –6y –8z = 4 d. x2 + y2 + z2 + 4x + 6y + 8z = 4 |
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Answer» Correct option a. x2 + y2 + z2 + 4x –6y –8z = 7 Explanation: (x + 2)2 + (y – 3)2 + (z – 4)2 = 62 ⇒ x2 + y2 + z2 + 4x – 6y – 8z = 62 – 22 – 32 – 42 ⇒ x2 + y2 + z2 + 4x – 6y – 8z = 7 |
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