1.

What is the equilibrium expression for the reaction: P_4(s)+5O_2(g) hArr P_4O_10(s)

Answer»

`K = [O_2]^5`
`K_c =([P_4O_10])/(5[P_4][O_2])`
`K_c=([P_4O_10])/([P_4][O_2]^5)`
`K_c=1/([O_2]^5)`

ANSWER :D


Discussion

No Comment Found