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What is the equilibrium expression for the reaction `P_(4(s)) + 5O_(2(g))hArrP_(4)O_(10(s))` ?A. `K_(c) = (1)/([O_(2)]^(5))`B. `K_(c) = ([P_(4)O_(10)])/(5[P_(4)][O_(2)])`C. `K_(c) = [O_(2)]^(5)`D. `K_(c) = ([P_(4)O_(10)])/([P_(4)][O_(2)]^(5))` |
Answer» Correct Answer - D `K_(p) = K_(c)xx(RT)^(Delta n)` `.: delta n = 1 - 2 = - 1` `:. K_(p) = K_(c)xx(RT)^(-1)` Or `(K_(p))/(K_(c)) = (1)/(RT)` |
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