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What is the equilibrium expression for the reaction `P_(4(s)) + 5O_(2(g))hArrP_(4)O_(10(s))` ?A. `K_(C)=[P_(4)O_(10)]//[P_(4)][O_(2)]^(5)`B. `K_(C)=1//[O_(2)]^(5)`C. `K_(C)=[O_(2)]^(5)`D. `K_(C)=[P_(4)O_(10)]//5[P_(4)][O_(2)]` |
Answer» Correct Answer - B `P_(4)(g)+5O_(2)(g)hArrP_(4)O_(10)(g) K_(C)=([P_(4)O_(10)(s)])/([P_(4)(s)][O_(2)(g)])^(5)` |
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