What is the equivalent time –domain expression of X+(F)=2V(F)X(F)?(a) F^(+1)[2V(F)]*F^(+1)[X(F)](b) F^(-1)[4V(F)]*F^(-1)[X(F)](c) F^(-1)[V(F)]*F^(-1)[X(F)](d) F^(-1)[2V(F)]*F^(-1)[X(F)]I had been asked this question in an online quiz.The doubt is from The Representation of Bandpass Signals topic in portion Sampling and Reconstruction of Signals of Digital Signal Processing

What is the equivalent time –domain expression of X+(F)=2V(F)X(F)?(a

1.	What is the equivalent time –domain expression of X+(F)=2V(F)X(F)?(a) F^(+1)[2V(F)]F^(+1)[X(F)](b) F^(-1)[4V(F)]F^(-1)[X(F)](c) F^(-1)[V(F)]F^(-1)[X(F)](d) F^(-1)[2V(F)]F^(-1)[X(F)]I had been asked this question in an online quiz.The doubt is from The Representation of Bandpass Signals topic in portion Sampling and Reconstruction of Signals of Digital Signal Processing
Answer» The CORRECT choice is (d) F^(-1)[2V(F)]F^(-1)[X(F)] To EXPLAIN I would say: Given EXPRESSION, X+(F)=2V(F)X(F).It can be calculated as follows \(x_+ (t)=\int_{-∞}^∞ X_+ (F)e^{j2πFt} dF\) =\(F^{-1} [2V(F)]F^{-1} [X(F)]\)

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