1.

what is the escape velocity of a body from the earth?

Answer»

Solution :`V_(e_1)sqrt((2GM)/R),=sqrt((2G4M)/(2R))=sqrt((8GM)/R)thereforeV_(e_2)=sqrt2xxsqrt((2GM)/R)=sqrt2xxV_(e_1)=1.414xx11.2=15:8m//s`.


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