1.

What is the first backward difference of y(n)?(a) [y(n)+y(n-1)]/T(b) [y(n)+y(n+1)]/T(c) [y(n)-y(n+1)]/T(d) [y(n)-y(n-1)]/TI had been asked this question in homework.My doubt is from Backward Difference Method in portion Digital Filters Design of Digital Signal Processing

Answer»

Right OPTION is (d) [y(n)-y(n-1)]/T

Explanation: A SIMPLE approximation to the FIRST ORDER derivative is given by the first backward difference. The first backward difference is defined by

[y(n)-y(n-1)]/T.



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