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What is the foot of the perpendicular from the point (2, 3) on the line `x+y-11=0` ?A. (1, 10)B. (5, 6)C. (6, 5)D. (7, 4)

Answer» Correct Answer - B
We jnow a line perpendicular to a given line
`ax-by+c=0` is `bx+ay+k=0`
`:.` The equation of line perpendicular to given line
`x+y-11=0` ...(i)
is `-x+y+lambda=0` ...(ii)
Since, this equation passes through (2, 3).
therefore (2, 3) satisfies the equation of line
`:. -2+3+lambda=0`
`implies lambda=-1`
`:.` From Eq. (ii),
`-x+y-1=0`
`implies y=x+1`
And from eq. (i),
`x+x+1-11=0`
`implies 2x=10`
`implies x=5`
Hence, coordinates of foot of perpendicular from (2, 3) to given line is (5, 6)


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