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    				| 1. | What is the foot of the perpendicular from the point (2, 3) on the line `x+y-11=0` ?A. (1, 10)B. (5, 6)C. (6, 5)D. (7, 4) | 
| Answer» Correct Answer - B We jnow a line perpendicular to a given line `ax-by+c=0` is `bx+ay+k=0` `:.` The equation of line perpendicular to given line `x+y-11=0` ...(i) is `-x+y+lambda=0` ...(ii) Since, this equation passes through (2, 3). therefore (2, 3) satisfies the equation of line `:. -2+3+lambda=0` `implies lambda=-1` `:.` From Eq. (ii), `-x+y-1=0` `implies y=x+1` And from eq. (i), `x+x+1-11=0` `implies 2x=10` `implies x=5` Hence, coordinates of foot of perpendicular from (2, 3) to given line is (5, 6) | |