Saved Bookmarks
| 1. |
What is the force required to seprate two glass plates of area 10^-2m^2 with a film of water of thickness 0.05mm between them surface tension of water 72xx10^-3 N/m? |
|
Answer» Solution :T = W/A or E/A `therefore W = F XX d` = 2TA ` `therefore F = 2TA/d = (2 xx 7 xx 10^-2 xx 3 xx 10^-2)/(0.07 xx 10^-3)` = `6 xx 10^1` = 60 N |
|