What is the form of the FIR system to compute the moving average of the signal x(n)?(a) y(n)=\(\frac{1}{M+1} \sum_{k=0}^M x(n-k)\)(b) y(n)=\(\frac{1}{M+1} \sum_{k=0}^M x(n+k)\)(c) y(n)=\(\frac{1}{M+1} \sum_{k=0}^{\infty} x(n-k)\)(d) None of the mentionedI got this question by my college professor while I was bunking the class.This interesting question is from Implementation of Discrete Time Systems topic in portion Discrete Time Signals and Systems of Digital Signal Processing

What is the form of the FIR system to compute the moving average of th

1.	What is the form of the FIR system to compute the moving average of the signal x(n)?(a) y(n)=\(\frac{1}{M+1} \sum_{k=0}^M x(n-k)\)(b) y(n)=\(\frac{1}{M+1} \sum_{k=0}^M x(n+k)\)(c) y(n)=\(\frac{1}{M+1} \sum_{k=0}^{\infty} x(n-k)\)(d) None of the mentionedI got this question by my college professor while I was bunking the class.This interesting question is from Implementation of Discrete Time Systems topic in portion Discrete Time Signals and Systems of Digital Signal Processing
Answer» The correct answer is (a) y(N)=\(\frac{1}{M+1} \sum_{k=0}^M x(n-k)\) For explanation: A normal FIR non-recursive system with the impulse response h(n)=\(\frac{1}{M+1}\) is the system which is USED to compute the moving AVERAGE of a signal x(n).

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